p^2+6p-81=0

Solution for p^2+6p-81=0 equation:

p^2+6p-81=0

a = 1; b = 6; c = -81;
Δ = b2-4ac
Δ = 62-4·1·(-81)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{10}}{2*1}=\frac{-6-6\sqrt{10}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{10}}{2*1}=\frac{-6+6\sqrt{10}}{2}
$